2X^2+3Y^2=10

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Solution for 2X^2+3Y^2=10 equation:


Simplifying
2X2 + 3Y2 = 10

Solving
2X2 + 3Y2 = 10

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-3Y2' to each side of the equation.
2X2 + 3Y2 + -3Y2 = 10 + -3Y2

Combine like terms: 3Y2 + -3Y2 = 0
2X2 + 0 = 10 + -3Y2
2X2 = 10 + -3Y2

Divide each side by '2'.
X2 = 5 + -1.5Y2

Simplifying
X2 = 5 + -1.5Y2

Reorder the terms:
-5 + X2 + 1.5Y2 = 5 + -1.5Y2 + -5 + 1.5Y2

Reorder the terms:
-5 + X2 + 1.5Y2 = 5 + -5 + -1.5Y2 + 1.5Y2

Combine like terms: 5 + -5 = 0
-5 + X2 + 1.5Y2 = 0 + -1.5Y2 + 1.5Y2
-5 + X2 + 1.5Y2 = -1.5Y2 + 1.5Y2

Combine like terms: -1.5Y2 + 1.5Y2 = 0.0
-5 + X2 + 1.5Y2 = 0.0

The solution to this equation could not be determined.

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